Which statement correctly describes the organization of cells, tissues, organs, and organ systems within a human body?

This speed is measured with respect to the space station the spacecraft was originally launched from. In interstellar space the

valentinak56 [21]

Answer:

15193.62 m/s

Explanation:

t = Time taken = 6.5 hours

u = Initial velocity = 0 (Assumed)

m = Mass of rocket = 1380 kg

F = Thrust force = 896 N

v = Final velocity

a = Acceleration of the rocket

Force

$F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{896}{1380}\\\Rightarrow a=0.6493\ m/s^2$

Equation of motion

$v=u+at\\\Rightarrow v=0+0.6493\times 6.5\times 60\times 60\\\Rightarrow v=15193.62\ m/s$

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s

5 0

3 years ago

What three structures to the bodies of all vascular plants have?? HELP!!!!

bearhunter [10]

All vascular plants have parenchyma, collenchymVascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes xylem, phloem, parenchyma, and cambium cells.a, and sclerenchyma cells. Hoped it help!

3 0

3 years ago

Pleaseeeeeee answer :3!

Ludmilka [50]

Work = (force) x (distance)

Work = (21 Newtons) x (9 meters) = 189 Joules

Power = (work done) / (time to do the work)

Power = (189 Joules) / (3 sec)

Power = (63 watts/sec)

Power = 63 watts (D)

3 0

3 years ago

A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize

Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × $10^{-19}$ C

and charge on iron will be q3 = 2 × 1.602 × $10^{-19}$ C

so charge on electron is q1 = - 1.602 × $10^{-19}$ C

and we know F = $k\frac{q*q}{r^{2} }$

so now by equilibrium

Fu = Fi

$k\frac{q*q}{r^{2} }$ = $k\frac{q*q}{r^{2} }$

put here k = $9*10^{9}$ and find r

$9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }$ = $9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }$

$\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}$

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

6 0

3 years ago

If you double the wavelength, the electromagnetic radiation energy will double. The energy of the electromagnetic radiation will

Sedbober [7]

Answer:

It's energy will double.

Explanation:

This is because energy, E, is related to frequency, f, by:

E = hf

Where h = Planck's constant

So, double frequency will be 2f

=> E(2f) = 2hf = 2E.

Hence, energy is doubled.

7 0

3 years ago