Given:
P1 = 400 kPa
T1 = 110 K
T2 = 235K
Required:
P2
Solution:
Apply Gay-Lussac’s
law where P/T = constant
P1/T1 = P2/T2
P2 = T2P1/T1
P2 = (235K)(400kPa)
/ (110K)
P2 = 855 kPa
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Answer:
The length of the incline is 3.504 meters.
Explanation:
Let suppose that Julietta's ball decelerates uniformly, then we determine the length of the incline is determined by the following equation of motion:
(Eq. 1)
Where:
- Length of the incline, measured in meters.
- Initial speed of the ball, measured in meters per second.
- Aceleration of the ball, measured in meters per square second.
- Time, measured in second.
If we know that 
, 
and 
, then the length of the incline is:
The length of the incline is 3.504 meters.
