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3 years ago

15

What is the area of the figure?

1 answer:

Anton [14]3 years ago

6 0

Answer: C

Explanation: Area of a square: A = a^2 = 6^2 = 36. Area of a circle: A = pi r^2 = pi • 6^2 = 113.1 but since that's 1/4 of a circle A = 113.1/4 = 28.275. 36 + 28.275 = 64.275

But since the area of a circle is exactly 113.08734 and I rounded to the nearest tenth, I'm sure it can be 64.26.

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Line A is represented by the following equation: x + y = 2

igomit [66]

Well if x+y=2, then it can't equal 4

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4 years ago

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What is the average rate of change of the function f(x) = - 3x + 5 over the interval x = - 1 to x = 1 ?

alukav5142 [94]

Answer:-3

Step-by-step explanation:

Given

F(x)=-3 x +5

in the interval x=-1 to x=1

Average rate of change is given by $=\frac{F(b)-F(a)}{b-a}$

over x=a to x=b

F(1)=-3+5=2

F(-1)=3+5=8

Thus average rate of change $=\frac{2-8}{1-(-1)}=-3$

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3 years ago

If y = 3x^3 - 2x and dx/dt equals 3, find dy/dt when x = -2. Give only the numerical answer. For example, if dy, dt = 4, type on

Nadya [2.5K]

Answer:

$\frac{dy}{dt} = 102$

Step-by-step explanation:

<u>step(i)</u>

Given function y = 3 x³ - 2 x ... (i)

Differentiating equation (i) with respective to 'x'

$\frac{dy}{dx} = 3 (3 x^{2} ) - 2(1)$

Given x = -2

$(\frac{dy}{dx} ) x_{=-2} = 3 (3 (-2)^{2} ) - 2(1)$

$(\frac{dy}{dx} ) x_{=-2} = 36 -2 =34$

<u><em>Step(ii):-</em></u>

<u><em>we know that </em></u>

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

Given $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

$\frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

substitute values $\frac{dx}{dt} = 3 and \frac{dy}{dx} = 34$

⇒ $34 = \frac{\frac{dy}{dt} }{3 }$

cross multiplication , we get

$\frac{dy}{dt} = 34( 3 ) = 102$

<u><em>Final answer</em></u>:-

$\frac{dy}{dt} = 34( 3 ) = 102$

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3 years ago