All categories

4 years ago

When a gas molecule is heated, there is an increase in the mass of the gas

Chemistry

2 answers:

Scorpion4ik [409]4 years ago

8 0

Answer:

True

Explanation:

When temperature increases, the kinetic energy of the gas molecule increases. Since kinetic energy is proportional to mass, also the mass increases.

insens350 [35]4 years ago

3 0

The answer would be true.

You might be interested in

Match the term with its description.

Fynjy0 [20]

Answer:

1 a 2c 3d 4b

Explanation:

I think that's right

3 0

3 years ago

If earth did not rotate what would happen to the global winds and why?

Anna35 [415]

If earth didn't rotate the global winds would stay on the same speed of rate because the wind isn't moving without rotation in the earths axis.

3 0

4 years ago

Read 2 more answers

Which statement correctly describes a reaction in dynamic equilibrium?

Andre45 [30]

Answer:

The answer is B - At dynamic equilibrium, the reactions continue but the amounts of reactants and products do not change.

Explanation:

got it right on Edge

4 0

3 years ago

______________ are caused by earth's internal heat sources.

quester [9]

Volcanic eruptions are caused by earth's internal heat sources.

All the other choices are atmospheric or external earth.

4 0

3 years ago

Read 2 more answers

Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl

Archy [21]

Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

$\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles$

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

$V\propto n$

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

where,

$V_1$ = initial volume of gas = V

$V_2$ = final volume of gas = 2V

$n_1$ = initial moles of gas = 1.56 mole

$n_2$ = final moles of gas = ?

Now we put all the given values in this formula, we get

$\frac{V}{2V}=\frac{1.56mole}{n_2}$

$n_2=3.12mole$

Now we have to calculate the mass of helium gas at doubled volume.

$\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He$

$\text{Mass of }He=3.12mole\times 4g/mole=12.48g$

Therefore, the mass of helium gas added must be 12.48 grams.

4 0

3 years ago