The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.
The given parameters;
- <em>mass of the sodium chloride, = 14.5 g</em>
- <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>
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In the reaction above, we can deduce the following;
molecular mass of 2Nacl = 2(58.44) = 116.88 g
molecular mass of 2NaF = 2(42) = 84 g
molecular mass of Cl2 = 71 g
The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 84 g of NaF
14.5 g of NaCl ------------------- ?
The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 71 g of Cl2
14.5 g of NaCl ------------------- ?
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Hydrogen i think. the orbital of hydrogen is peculiar
0.0001 is the objects mass because you go from mili, to centi, deci, gram, deca, hecta, Kila. that's 6 decimal points which is what times you 3 zeroes before the 1. The decimal point started out at the end of 100 and moved 6 places to be 0.0001
Answer:
A = Molarity = 0.22 M
B = Molarity = 0.36 M
Explanation:
Given data:
For first solution:
number of moles = 0.550 mol
Volume of solution = 2.50 L
Molarity = ?
Molarity:
Formula:
Molarity = number of moles of solute / volume of solution in L.
Molarity = 0.550 mol / 2.50 L
Molarity = 0.22 M
For second solution:
Mass of NaCl = 15.7 g
Volume of solution = 709 mL or 709/1000 = 0.709 L
Molarity = ?
Solution:
Number of moles = mass / molar mass
Number of moles = 14.7 g/ 58.44 g/mol
Number of moles = 0.252 mol
Molarity:
Molarity = number of moles of solute / volume of solution in L.
Molarity = 0.252 mol / 0.709 L
Molarity = 0.36 M
Answer:
Below:
Explanation:
An iron will use 800 to 2000 watts, with an average iron using 1100 watts when heated on high.
