<u>Answer:</u> 72 grams of water will be produced.
<u>Explanation:</u>
To calculate the number of moles, we use the formula:
....(1)
Mass of propane = 44 grams
Molar mass of propane = 44 grams
Putting values in above equation, we get:

For the reaction of combustion reaction of propane, the equation follows:

By Stoichiometry of the reaction,
1 mole of propane produces 4 moles of water.
So, 1 mole of propane will produce =
of water.
Now, to calculate the amount of water, we use equation 1, we get:
Molar mass of water = 18 g/mol

Mass of water produced = 72 grams
Hence, 72 grams of water will be produced.