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2 years ago

5

Rhombus EFGH is rotated 90 degrees counterclockwise about vertex G. How many pairs of parallel sides does the rotated figure hav

e?
Please explain your answer.... Thank you!

A) 0

B) 1

C)2

D) 4

1 answer:

Mars2501 [29]2 years ago

4 0

Answer:

try your self more and more times you can easily solve

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Step-by-step explanation:

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Step-by-step explanation:

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Then solve!

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2 years ago

Find the focus. y= -1/12 (x)² - 6

jolli1 [7]

Answer:

$\Large \boxed{\sf\ \ (0,-9) \ \ }$

Step-by-step explanation:

Hello,

We know that when the parabola equation is

$y=a(x-h)^2+k$

the vertex is (h,k) and the focus is

$(h,k+\dfrac{1}{4a})$

Here, the equation is

$y=-\dfrac{1}{12}x^2-6$

so

$a=-\dfrac{1}{12}\\\\h = 0\\\\k =-6$

So,

$k+\dfrac{1}{4a}=-6-\dfrac{12}{4}=-6-3=-9$

Then, the focus is

$\large \boxed{\sf\ \ (0,-9) \ \ }$

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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