Answer:The answers are: 4 40 56 96.
We have 7 people which result ----> 7 * <u />2 = <u>14 legs</u>
Also, the table has <u>4 legs</u>
The number of the big cats is 7 *7 =49 (big cats)
For every big cat we have ---> 49 * 4= <u>196 legs</u>
For every big cat we have 7 small cats which means --> 49 * 7= 343 (small kittens)
The number of legs for small kittens is 343 * 4 = <u>1372 legs</u>
The number of legs is:
<u />
<u>14+4+196+1372= 1586 legs are in total</u>
The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:
S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people
We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:
Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer
Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.
Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.
A) (-2,4)
first multiply 2nd eqn by 2 and subtract it from eqn 1st then u will get x then put x in ist eqn then u will get y.
