Both Chemical and Nucleus Reactions form new substances.
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Answer:
2.63g
This means that every mole of water molecules will contain 2 moles of hydrogen and 1 mole of oxygen atoms.
To find the percent composition of hydrogen in water, use the molar mass of water and that of hydrogen
2×1.00794g/mol18.0153g/mol×100=11.19%
This means that every 100 g of water will contain a total of 11.19 g of hydrogen. Since your sample has a mass of 23.5 g, it follows that it will contain
23.5g water⋅11.19 g H100g water=2.63 g H
Answer:
Atomic mass of element X = 115 g/mol (Approx)
Explanation:
Given:
Amount of XCl3 = 10.69 gram
Amount of X = 5.55 gram
Find:
Atomic mass of element X
Computation:
Moles of Cl = [Mass of Cl / Molar mass of Cl )
Moles of Cl = [(10.69 - 5.55 ) / 35.5]
Moles of Cl = 0.14479 (Approx)
Moles of X = 0.14479 / 3
Moles of X = 0.04826
Atomic mass of element X = 5.55 / 0.04826
Atomic mass of element X = 115 g/mol (Approx)
Answer is: the molecular formula is C₆H₁₀.
Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.
m(H₂O) = 0.9102; mass of the water.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,9102 g ÷ 18 g/mol
n(H₂O) = 0,0505 mol.
From chemical reaction: n(H) = 2 · n(H₂O).
n(H) = 0.101 mol.
m(CO₂) = 2.668 g; mass of carbon dioxide.
n(CO₂) = 2.668 g ÷ 44 g/mol.
n(CO₂) = 0.0606 mol; amount of the substance.
n(CO₂) = n(C) = 0.0606 mol.
n(C) : n(H) = 0.606 mol : 0.101 mol.
n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.
