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Ann [662]
2 years ago
8

Certain race cars use methanol (CH 3 OH) as fuel. The combustion of 9.8 moles of methanol produces what mass of water?

Chemistry
1 answer:
IrinaK [193]2 years ago
3 0

Answer: Moles of CH3OH = 9.8 moles

The given equation for combustion of methanol is,

2 CH3OH (l) + 3 O2(g) → 2CO2 (g) + 4 H2O(l)

The moles of water can be calculated from the above balanced equation i.e 2 mol of CH3OH  on combustion forms 4 moles of H2O.

Thus the number of mole of H2O = 9.8 mol CH3OH = 20 mol H2O

Thus the number of moles of water has found to be 20 mol H2O.

Explanation:

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valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

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Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.
Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

  • molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

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How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
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The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>
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  • Volume of acid, HCl (Va) = 36 mL
  • Molarity of acid, HCl (Ma) = 1.63 M
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MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

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Cross multiply

2 × 1.48 × Vb = 58.68

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Divide both side by 2.96

Vb = 58.68 / 2.96

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