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2 years ago

Certain race cars use methanol (CH 3 OH) as fuel. The combustion of 9.8 moles of methanol produces what mass of water?

Chemistry

1 answer:

IrinaK [193]2 years ago

3 0

Answer: Moles of CH3OH = 9.8 moles

The given equation for combustion of methanol is,

2 CH3OH (l) + 3 O2(g) → 2CO2 (g) + 4 H2O(l)

The moles of water can be calculated from the above balanced equation i.e 2 mol of CH3OH on combustion forms 4 moles of H2O.

Thus the number of mole of H2O = 9.8 mol CH3OH = 20 mol H2O

Thus the number of moles of water has found to be 20 mol H2O.

Explanation:

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What is the name of this molecule?

Sunny_sXe [5.5K]

Answer:

D. cis-2-pentene (looks like a frying pan)

Explanation:

pentane looks lihe the letter M

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2 years ago

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

Explanation:

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

$100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}$

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0

3 years ago

Study the picture below. Done!! Thanks

myrzilka [38]

The rabbit and the girl are living things.

The shoe and the skirt are non-living things.

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2 years ago

Estimate the enthalpy change for the combustion of one mole of acetylene, C2H2, to form carbon dioxide and water vapor. BE(C?H)

tia_tia [17]

Answer:

ΔH rxn = -1010 kJ/molC₂H₂

Explanation:

To obtain the enthalpy change for a reaction from bond energies what we do is to make an inventory of the bonds broken and formed for the balanced chemical reaction:

C₂H₂ + 5/2O₂ ⇒ 2CO₂ + H₂O

Bond Broken Bonds Formed

2 C-H + 1 C≡C + 5/2 O=O 4C=O + 2 H-O

Enthalpy bonds broken:

2 mol (456 kJ/mol)+ 1 mol (962 kJ/mol) + 5/2 mol (499 kJ/mol) = 3121.5 kJ

Enthalpy bond formed:

4 mol (802 kJ/mol) + 2 mol (462 kJ/mol) = 4132.0 kJ

ΔH rxn = H broken - H formed = 3121.5 kJ - 4132.0 kJ = - 1010 kJ (per mol C₂H₂ )

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2 years ago

Iron sulfite has the formula?

Mademuasel [1]

Its FeSO3 or iron(iii)sulfite = Fe2(SO3)3

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3 years ago