A large interquartile range shows the range in values of the central 50% of the data.
Grab your calculator and enter 16231 then the divide key then 23 and finally = or exe.
you should get 705.696 to nearest thousandth.
Width = 70yd
Length = 105yg
2(65+110) = 2(70+105)
But 65*110 = 7150
And 70*105 = 7350
So 70*105 > 65*110
<em>The regular price was $110</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em />
<em>60% .......... $66</em>
<em>100% ..........$ x</em>
<em>x = 100×66/60</em>
<em>= 6600/60</em>
<em>= $ 110</em>
<em />
<em>Good luck !</em>
Answer:
<h2>Bibi ate 6.3 pounds of food, approximately.</h2><h2>Rexy ate 5.7 pounds of food, approximately.</h2>
Step-by-step explanation:
1. What is this situation about?
The situation described is about the amount of food those dogs eat, and its relation with their weights.
2. What are the quantities in this situation?
The quantities are aboth the weight of each dog, and the number of pounds of dog food.
3. What mathematical questions could we ask?
We could ask the pounds of food each dog eats, in proportion with their weights.
4. Answer the question.
To answer that question, we just need to form a proportion.

Where
is the total pounts Rexy ate, and
is the total pounts Bibi ate.

Therefore, Bibi ate 6.3 pounds of food, approximately.
Then, 
Which means, Rexy ate 5.7 pounds of food, approximately.