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juin [17]
3 years ago
15

A particle traveled the distance of 6.6×

"10^{-19}" align="absmiddle" class="latex-formula"> meters a a rate of 3.3×10^{-34}. If distance equals rate times time, how many seconds did it take the particle to travel the specified distance?
A. 5.0x10^{14} seconds
B. 2.0x10^{15} seconds
C. 2.0x10^{-53} seconds
D. 5.0x10x^{-53} seconds
Mathematics
2 answers:
NeTakaya3 years ago
8 0

Answer:

Distance (D) equals rate (R) times time (T): D = R x T

=> T = D/R = 6.6 x 10^-19/(3.3 x 10^-34) = 2 x 10^15 (m)

=> Option B is correct

Hope this helps!

:)

Gemiola [76]3 years ago
5 0

Answer:

dflgbnjmjnhgfdsasdvb

Step-by-step explanation:

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three consecutive odd integers are.

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Let x be the first term of odd integer,

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