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juin [17]
3 years ago
15

A particle traveled the distance of 6.6×

"10^{-19}" align="absmiddle" class="latex-formula"> meters a a rate of 3.3×10^{-34}. If distance equals rate times time, how many seconds did it take the particle to travel the specified distance?
A. 5.0x10^{14} seconds
B. 2.0x10^{15} seconds
C. 2.0x10^{-53} seconds
D. 5.0x10x^{-53} seconds
Mathematics
2 answers:
NeTakaya3 years ago
8 0

Answer:

Distance (D) equals rate (R) times time (T): D = R x T

=> T = D/R = 6.6 x 10^-19/(3.3 x 10^-34) = 2 x 10^15 (m)

=> Option B is correct

Hope this helps!

:)

Gemiola [76]3 years ago
5 0

Answer:

dflgbnjmjnhgfdsasdvb

Step-by-step explanation:

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mars1129 [50]

Answer:

1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},

Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

Exponent property used: a^b\cdot a^c=a^{(b+c)}, yielding an answer of \boxed{5}

4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}

3 0
3 years ago
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Step-by-step explanation:

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Matthew sorts some figures. He includes a regular hexagon with only figures 2 and 3.
kykrilka [37]

Answer:

B.

Step-by-step explanation:

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3 0
3 years ago
Equation with angle addition can someone please answer please help
marishachu [46]

Answer:

57°

Step-by-step explanation:

We can see that LOM is MON + LON so we can set up an equation to find the value of x then substitute that back into MON to find the value of that angle.

→ In equations its important to keep both sides equal and do operations to both sides and not one because then if you do an operation to only one side then you have changed the equation so it's important to do operations on both sides and that's an important rule to bare in mind.

2x + 33 + 3x + 20 = 113

→ Simplify

5x + 53 = 113

→ Minus 53 from both sides to isolate 5x

5x = 60

→ Divide both sides by 5 to isolate x

x = 12

But we are not finished, we have only found the value of x not the value of MON as we were asked so we have to substitute x back into the expression to find the value of MON

2x + 33

→ Substitute x = 12 back into the expression

2 × 12 + 33

→ Simplify

24 + 33 = 57

The value of MON is 57°

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