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Lesechka [4]
3 years ago
8

NEED HELP ASAPPP What is the number of beryllium atoms in 78.0g of Be?

Chemistry
1 answer:
polet [3.4K]3 years ago
4 0

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

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Answer:

We need 375 milliliters of 0.100 M NaHCO3 solution

Explanation:

Step 1: Data given

Initial molarity NaHCO3 = 0.100 M

Volume prepared solution = 750.0 mL

Molarity prepared solution = 0.05 M

Step 2: Calculate initial volume

C1*V1 = C2V2

⇒with C1 = the initial concentration = 0.100 M

⇒with V1 = The initial volume = TO BE DETERMINED

⇒with C2 = the new concentration = 0.0500M

⇒with v2 = the new volume = 750.0 mL = 0.750 L

0.100 M * V1 = 0.0500 M * 0.750 L

V1 = (0.0500M * 0.750L)/0.100 M

V1 = 0.375 L = 375 mL

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