NEED HELP ASAPPP What is the number of beryllium atoms in 78.0g of Be?

Chemistry

1 answer:

polet [3.4K]3 years ago

4 0

Answer: number of atoms is 5.21 · 10^24

Explanation: Atomic mass of Be is 9.012 g/mol.

Number of moles n = m/M = 78.0 g / 9.012 g/mol =

Multiply this with Avogadro number Na = 6.022*10^23 1/mol

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