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Novay_Z [31]
3 years ago
13

15.0 g of cream at 10.0 ℃ are added to an insulated cup containing 150.0 g of coffee at 78.6 °C. Calculate the equilibrium tempe

rature of the coffee. You may assume no heat is lost to the cup or surroundings, and that any physical properties of cream and coffee you need are the same as those of water Be sure your answer has 3 significant digits. _____________⁰C
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

The equilibrium temperature of the coffee is 72.4 °C

Explanation:

Step 1: Data given

Mass of cream = 15.0 grams

Temperature of the cream = 10.0°C

Mass of the coffee = 150.0 grams

Temperature of the coffee = 78.6 °C

C = respective specific heat of the substances( same as water) = 4.184 J/g°C

Step 2: Calculate the equilibrium temperature

m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)

15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)

62.76T2 - 627.6 = -627.6T2 + 49329.36

690.36T2 = 49956.96

T2 = 72.4 °C

The equilibrium temperature of the coffee is 72.4 °C

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Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

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V_s = volume of solution in L

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moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

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Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

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We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

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3 years ago
Acetone (nail polish remover) has a density of 0.7857 g >cm3.
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If acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

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In the statement we can find that acetone has a density of 0.7857 \frac{g}{cm^{3} }.

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。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe the answer would be A. equal temperature

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