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Gwar [14]
3 years ago
5

A basketball coach plotted data about her shooting guard’s playing time and point scoring in a scatterplot. Shooting Guard Minut

es Played and Points Scored A graph has minutes played on the x-axis, and points scored on the y-axis. A line goes through points (8, 6) and (30, 21). Which is the equation of the line of best-fit? y = StartFraction 15 Over 22 EndFraction x + StartFraction 6 Over 11 EndFraction y = StartFraction 15 Over 22 EndFraction x + StartFraction 43 Over 11 EndFraction y = StartFraction 22 Over 15 EndFraction x minus StartFraction 86 Over 15 EndFraction y = StartFraction 22 Over 15 EndFraction x minus four-fifths
Mathematics
2 answers:
Inessa [10]3 years ago
5 0

Answer:

it a

Step-by-step explanation:

Roman55 [17]3 years ago
4 0

Answer:

The answer is y = StartFraction 15 Over 22 EndFraction x + StartFraction 6 Over 11 EndFraction → y = 15/22x + 6/11

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Jason went to the Hamburger Shack twice last week.
WARRIOR [948]

Answer:

Cost of 1 hamburger = $1.3

Step-by-step explanation:

Assume;

Cost of 1 hamburger = a

Cost of 1 French fries = b

On first trip

3a + 4b = 7.10......eq1

On second trip

2a + b = 3.40....eq2

From eq2 x 4

8a + 4b = 13.6....eq3

From eq3 - eq1

5a = 6.5

a = 1.3

Cost of 1 hamburger = $1.3

7 0
3 years ago
PLEASE HELP I WILL MARK BRAINLIEST!!
agasfer [191]
2 times x -4=12
2x-4=12
Let x= 8
(2.8)-4=12
16-4= 12

So the answer is 8
8 0
3 years ago
Exact length of line segment xy
netineya [11]
length=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
4 0
4 years ago
Beulah used 3/5 pounds of dough, 3/4 pound of sugar, & 2/3 pounds of sprinkles to make donuts. How many pounds of donuts did
andre [41]

Number of pounds of dough used = 3/5 pounds.

Number of pounds of sugar used = 3/4 pounds

Number of pounds of sprinkles used = 2/3 pounds.

Total number of pounds of donuts = Number of pounds of dough used + Number of pounds of sugar used + Number of pounds of sprinkles used.

Plugging values.

Total number of pounds of donuts = 3/5 + 3/4 + 2/3.

We need to add all those fractions.

In order to add fracions, we need to find common denominator (lcd).

We have 5,4 and 3 in denominators.

Least common denominator(lcd) of 5, 4 and 3 is 60.

We need to make each denominator equals 60.

Multiplying first fracion by 12 in top and bottom, we get

3*12/5*12 = 36/60

Multiplying first fracion by 5 in top and bottom, we get

3*15/4*15 = 45/60

Multiplying first fracion by 20 in top and bottom, we get

2*20/3*20 = 40/60.

Therefore,

3/5 + 3/4 + 2/3 = 36/60 + 45/60 + 40/60

               =  121/60

Let us convert 121/60 into mixed fraction.

Dividing 121 by 60 we get quotient =2 and remainder =1.

So, the mixed fraction is 2 1/60.

Therefore, Beulah made total 2 1/60 pounds of donuts.

4 0
4 years ago
Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti
Vikki [24]

Answer:

General Solution is y=x^{3}+cx^{2} and the particular solution is  y=x^{3}-\frac{1}{2}x^{2}

Step-by-step explanation:

x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}

This is a linear diffrential equation of type

\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)..................(i)

here p(x)=\frac{-2}{x}

q(x)=x^{2}

The solution of equation i is given by

y\times e^{\int p(x)dx}=\int  e^{\int p(x)dx}\times q(x)dx

we have e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}

Thus the solution becomes

\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+cy=x^{3}+cx^{2

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have 6=8+4c

Thus solving for c we get c = -1/2

Thus particular solution becomes

y=x^{3}-\frac{1}{2}x^{2}

5 0
4 years ago
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