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Tatiana [17]
4 years ago
8

What is the problem to this a²+27a+72=0

Mathematics
2 answers:
zlopas [31]4 years ago
7 0
a^2+27a+72=0\\\\a^2+3a+24a+72=0\\\\a(a +3 )+24(a+3)=0\\\\(a+3)(a+24)=0\\\\a+3=0\ \ \vee \ \ a+24=0\\\\a=-3 \ \ \vee \ \ a=-24


Vinil7 [7]4 years ago
6 0
A² + 27a + 72 = 0
a = <u>-27 +/- √(27² - 4(1)(72))</u>
                     2(1)
a = <u>-27 +/- √(729 - 288)</u>
                     2
a = <u>-27 +/- √441
</u>                2
a = <u>-27+/- 21</u>
             2
a = <u>-27 + 21</u>        a = <u>-27 - 21</u>
             2                         2
a = <u>-6</u>                  a = <u>-48</u>
       2                           2
a = -3                  a = -24
<u />
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svp [43]

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7 0
3 years ago
Use the distributive property to write an equivalent expression <br><br> 5(6y - 5b + 1)
pav-90 [236]

Answer: 30y - 25b +5

Step-by-step explanation:

(look at attachment image fir explanation)

6 0
3 years ago
I NEED HELP BADLY!!!
DaniilM [7]
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4 0
3 years ago
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Evaluate the expression. If necessary, round to the nearest hundredth. ln 0
STatiana [176]
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7 0
3 years ago
What is the value of y?
nata0808 [166]

Answer: y = 16.5

Step-by-step explanation:

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Considering triangle BCD,

BD² = 14² - 8²

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BD = √132

Considering triangle ABD,

AB² = BD² + y²

AB² = (√132)² + y²

AB² = 132 + y²- - - - - - - - - - 1

Considering triangle ABC,

(8 + y)² = AB² + BC²

(8 + y)² = AB² + 14²

(8 + y)² = AB² + 196

AB² = (8 + y)² - 196- - - - - - - -2

Substituting equation 1 into equation 2, it becomes

132 + y² = (8 + y)² - 196

y² - (8 + y)² = - 196 - 132

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y² - 64 - 16y - y2 = - 328

- 16y = - 328 + 64

- 16y = - 264

y = - 264/- 16

y = 16.5

6 0
3 years ago
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