All categories

3 years ago

Rounding each number to the nearest tenth

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

Answer: (17.310 would round up to 18) (7.14 would round down to just 17) So your new equation will be 18 + 17 =35

Step-by-step explanation:

You might be interested in

Based on the 2009 season, the Texas Rangers have a winning percentage of .533. Use the binomial model to find the probability th

Naddik [55]

Answer:

0.128

Step-by-step explanation:

We know the probability for any event X is given by,

$P(X=x)=\binom{n}{x}\times p^{n-x}\times q^{x}$ ,

where p is the probability of success and q is the probability of failure.

Here, we are given that p = 0.533.

Since, we have that q = 1 - p

i.e. q = 1 - 0.533

i.e. q = 0.467

It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.

Substituting the values in the above formula, we get,

$P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}$

i.e. $P(X=4)=5 \times 0.533 \times 0.048$

i.e. i.e. $P(X=4)=0.128$

Hence, the probability of 4 wins in the next 5 games is 0.128.

8 0

2 years ago

Read 2 more answers

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$