Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
Answer:
i think E TO E
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
to find this divide big/small
75/12.5 = 6
so 6 small containers = 1 large one
Answers:
a = 2
b = 3
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Explanation:
Plug in x = 0 and y = 2 to find that
y = a*b^x
2 = a*b^0
2 = a*1
2 = a
a = 2
Then plug in x = 3 and y = 54 to determine the value of b
y = a*b^x
y = 2*b^x
54 = 2*b^3
2b^3 = 54
b^3 = 54/2
b^3 = 27
b = (27)^(1/3)
b = 3
So we have y = a*b^x update to y = 2*3^x
