If 3 xa 30, then A 4-3 B. a=1 c a=30 D a=0. E. a = 10
1 answer:
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Answer:
Step-by-step explanation:
We can solve this in either of two approaches: Mathematically or Graphically.
<u>Mathematically</u>
y=-(3/4)(x-4)^2+12 where y is the height of the ball, and x is the time, in seconds.
We want to know how many seconds for the height to be 0, so y=0.
0 = -(3/4)(x-4)^2+12
-12 = -(3/4)(x-4)^2
12*(4/3) = (x-4)^2
16 = (x-4)^2
x = 8 and 0 (the initial point).]
It will reach the ground in 8 seconds
<u>Graphically</u>
Plot the function and find the time, x, when the graph passes through the x axis (after t = 0). Attached.
Answer:
I guess this systems has 3 different solution
Step-by-step explanation:
(x,y,z) (32/15,-2/5,-11/15)
