Hello :
the tangent has same slope of the line 16x -y +5 = 0 because parallel.
y = 16x + 5
the slope is : 16
but : f'(x) = 16
f'(x) = 16x^3 - 16x +16
solve : 16x^3 - 16x +16 = 16
x^3 - x +1 =1
x^3 - x = 0
x(x² - 1 ) =0
x(x -1 )(x +1) =0
x=0 or x-1 =0 or x +1= 0
x=0 or x = 1 or x = -1
if : x = 0 : y = 4(0)^4 -8(0)^2+16(0) +7 =7
if : x =1 : y = 4(1)^4 -8(1)^2+16(1) +7 = 19
if : x = -1 : y = 4(-1)^4 -8(-1)^2+16(-1) +7 = -13
<span>the points : A(0,7) , B(1 , 19) , c ( -1 , -13)</span>
Answer:
A is right
B is acute
C is obtuse
D is right
Step-by-step explanation:
90 is right
anything under 90 is acute
over 90 obtuse
Answer:
C
Step-by-step explanation:
Answer:
1440
Step-by-step explanation:
using the formula (n-2)
8×180=1440
Answer:
125
Step-by-step explanation:
5^3 = 5 x 5 x 5
5 x 5 x 5 = 25 x 5
25 x 5 = 125
