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3 years ago

The structural layers of the sun are shown in the cross-sectional diagram.

Physics

2 answers:

Gelneren [198K]3 years ago

5 0

Answer:

The Corona is the outermost atmosphere of the sun, there is no picture so I can only guess that it's the 6th layer.

I hope this helps!

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

Explanation:

the corona is the outermost layer!

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At resonance, what is impedance of a series RLC circuit? less than R It depends on many other considerations, such as the values

denis23 [38]

Answer:

at resonance impedence is equal to resistance and quality factor is dependent on R L AND C all

Explanation:

we know that for series RLC circuit impedance is given by

$Z=\sqrt{R^2+\left ( X_L-X_C \}right )^2$

but we know that at resonance $X_L=X_C$

putting $X_L=X_C$ in impedance formula , impedance will become

Z=R so at resonance impedance of series RLC is equal to resistance only

now quality factor of series resonance is given by

$Q=\frac{\omega L}{R}=\frac{1}{\omega CR}=\frac{1}{R}\sqrt{\frac{L}{C}}$ so from given expression it is clear that quality factor depends on R L and C

3 0

3 years ago

Four resistors (67 ohm, 83 ohm, 433 ohm, and 309 ohm in that order) are connected in series to a 7.92 V battery of negligible in

Whitepunk [10]

Answer:

.737 v

Explanation:

Since they are in series....they all have the same current running through them.....find the total resistance to calculate the current:

R = 67 + 83 + 433 + 309 = 892 ohm

V/R = current = 7.92 / 892 = 8.87 mAmps

Now the voltage across ecah resistor is I R

for the second one 8.87 ma * 83 ohm = V = .737 V

7 0

3 years ago

A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o

Crank

To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

$\delta = \frac{PL}{AE}$

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

$P = 68*10^3 N$

E = 200GPa

$A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2$

Replacing we have,

$\delta = \frac{PL}{AE}$

$\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}$

$\delta = 0.001932m$

$\delta = 1.93mm$

Therefore the change in length is 1.93mm

7 0

3 years ago

Which of Galileo’s discoveries were later used in Newton’s laws?

Mrrafil [7]

Answer:

a moving object will keep moving if not stopped

the sun being at the center of the solar system

Explanation:

Galileo is known for being the first person make a telescope, there fore being the first person to see that the sun is in the center of the solar system. he also came up with the theory that if something is pushed, it would keep moving until stopped by another force. For example, say you drop your pencil, it keeps falling until it hits the ground. That is exactly what Galileo did in his Leaning Tower of Pisa experiment and found that theory to be true.

5 0

3 years ago

Under which set of circumstances will the pressure of a gas DEFINITELY increase?

malfutka [58]

Temperature increase, smaller container, or influx of more gas

5 0

4 years ago