Answer:
Explanation:
Given
height of wall=5.15 m
angle of launch
Launch velocity(u)=52.4 m/s
Time of flight will be sum of time of flight of projectile+time to cover 5.15 m
Time of flight of arrow
Now time require to cover 5.15 m
Here at the time of zero vertical displacement of arrow i.e. when arrow is at the same height as of building then its vertical velocity will change its sign compared to initial vertical velocity.
at zero vertical displacement
Thus time required will be 
total time =
(b)Horizontal distance=Range of arrow(R_1) + horizontal distance in 0.118 s
=263.28+3.546=266.82 m
Answer:
If the number of organisms and biomass is in a proper proportion at different trophic levels in a region, the environment in that region is said to be balanced. This balance can get disturbed due to natural hazards or by human intervention.
Answer:
The charge in each ball will be 3 * 10^-12 C
Explanation:
(Assuming the correct charge of the second ball is 8 * 10^-12)
When the balls are brought in contact, all the charges are split evenly among then.
So first we need to find the total charge combined:
(-3 * 10^-12) + (8 * 10^-12) + (4 * 10^-12) = 9 * 10^-12 C
Then, when the balls are separated, each ball will have one third of the total charge, so in the end they will have the same charge:
(9 * 10^-12) / 3 = 3 * 10^-12 C
So the charge in each ball will be 3 * 10^-12 C
V=0 v²=0, A=v-u/t. T=v-u/a. T= 0-9.32/-4.06 therefore time = 2.296 seconds
