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Bingel [31]
3 years ago
9

A metalworker has a metal alloy that is 15% copper and another alloy that is 65% copper. How many kilograms of each alloy should

the metalworker combine to create 50 kg of a 45% copper alloy? PLZZZ ANSWER QUICK
40 PTS!!!
Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

The answer is  60 kg of a 42% alloy, we'd need 24 kg of 15% copper and 36 kg of 60%

Step-by-step explanation:

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Which of this fraction are greater then1/2 but less then 3/4 .7/8 .2/5 .1/3 .5/8 .3/6
avanturin [10]

Answer: 7/8


Step-by-step explanation:

think of each faction as a pie or pizza.

each one will have the number of slices as the bottom number of the fraction.

now shade in the top numbers and see if it more than your 1/2

you will see 7/8 is the answer since it will be one piece left from being complete or "gone"

hope this helped angel!!


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Find the equation of the Circle P.
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Answer:

the anwers is 5

Step-by-step explanation:

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An expression is shown 342 / 8 What is the quotient expressed as a fraction?
tekilochka [14]
/ also means division so the answer is 42.75
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4 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





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3 years ago
105 is 150% of what number
zhannawk [14.2K]

Answer:

105 is 150% of 70.

Step-by-step explanation:


8 0
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