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luda_lava [24]
3 years ago
13

Given the function f(x) = 4^x - 1, explain and show how to find the average rate of change between x = 1 and x = 4.

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

84

Step-by-step explanation:

f(1)=4^1 - 1 = 3

f(4) = 4^4 - 1 = 255

rate of change = \frac{f(x_2)-f(x_1)}{x_2-x_1}

(255 - 3) / (4 - 1) = 252 / 3 = 84

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Helppppppp show the steps to your answer
Studentka2010 [4]

The numeric value of the expression -a² - 2bc - |c| for a = -3, b = -5 and c = 2 is of 9.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of an expression is found replacing each letter by it's attributed value.

In this problem, the expression is:

-a² - 2bc - |c|

The attributed values are:

a = -3, b = -5 and c = 2

Hence the numeric value will be given by:

-a² - 2bc - |c| = -(-3)² - 2(-5)(2) - |2| = -(9) + 20 - 2 = -9 + 18 = 9.

More can be learned about the numeric value of an expression at brainly.com/question/14556096

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4 0
1 year ago
Which product will be positive?
Sladkaya [172]

Answer:

-7 × (-4) will have a positive product.

Step-by-step explanation:

product of the two number are positive only if the two numbers have the same sign either both (+) or both (-).

and -7 × (-4) = 28.

here 28 is positive.

6 0
3 years ago
Person 1 writes internal operating procedures 3 times faster than Person 2. Most of the procedures took 30 minutes each to creat
ad-work [718]

Person 1 takes 3 hour 10 minutes to complete 9 procedures

<em><u>Solution:</u></em>

From given question,

Person 2 takes 30 minutes per procedure

Person 1 writes internal operating procedures 3 times faster than Person 2

So we get, Person 1 takes 3 times faster than Person 2

Person 1 takes 10 minutes per procedure

But two of the procedures for Person 1 took an hour each

So person 1 takes 60 minutes each for two of procedures ( since 1 hour = 60 minutes )

<em><u>Calculate how long it took Person 1 to complete 9 procedures:</u></em>

So for first 7 procedures person 1 would take 10 minutes per procedure and for last two procedures person 1 would take 60 minutes per procedure

time $=7$ procedures $\times \frac{10 \text { minutes }}{1 \text { procedure }}+2$ procedure $\times \frac{60 \text { minutes }}{1 \text { procedure }}$

time=70 minutes +120minutes\\\\time=190minutes

We know that,

1 hour = 60 minutes

Therefore,

190 minutes = 60 minutes + 60 minutes + 60 minutes + 10 minutes

190 minutes = 1 hour + 1 hour + 1 hour + 10 minutes = 3 hour 10 minutes

Therefore Person 1 takes 3 hour 10 minutes to complete 9 procedures

7 0
3 years ago
A movie theater complex gave a poll as viewers exited from two theaters showing the same film. They had a 20% response rate from
sp2606 [1]

Answer:

Let´s define the variables:

x = number of people in theater A

y = number of people in theater B

We know that a 20% (or 0.2 in decimal form) of the people in theater A answered the survey, then the number of people from theater A that answered the survey is: Na = 0.2*x

We know that a 30% (or 0.3 in decimal form) of the people in theater B answered the survey, then the number of people from theater B that answered the survey is: Nb = 0.3*y

There where 800 people in total (counting from the two theatres)

Then x + y = 800.

A) In this case we have:

Na = Nb

this means that:

0.2*x = 0.3*y

and we also have the equation:

x  + y = 800

To solve this, we need to isolate one variable in one of the equations, i will isolate x in the second equation:

x = 800 - y

And now we can replace this in the other equation to get:

0.2*(800 - y) = 0.3*y

We need to solve this for y:

160 - 0.2*y = 0.3*y

160 = 0.3*y + 0.2*y = 0.5*y

160/0.5 = y = 320

Then there where 320 people in theater B, and:

x + y = 800

x + 320 = 800

x = 800 - 320 = 480

There where 480 people in theather A.

B) Now we have:

x = 440

y = 360

then:

Na = 0.2*440 = 88

In theater A, 88 people answered the survey.

Nb = 0.3*360 = 108

In theater B, 108 people answered the survey.

In total, 88 + 108 = 196 people answered the survey.

5 0
3 years ago
As part of a screening process, computer chips must be operated in an oven at 125 °C. At the end of the cycle, the oven must be
Tasya [4]
I got 22.5 
 
tell me if i got it wrong or right
3 0
4 years ago
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