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alisha [4.7K]
3 years ago
12

List the angles of the triangle in order from smallest to largest

Mathematics
1 answer:
Scilla [17]3 years ago
4 0
P, whatever the top letter is, m
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Estimate the difference. Use benchmarks with decimal parts of 0, 0.25, 0.50, or 0.75.
Firdavs [7]
Your real exact answer would be 0.29 but a bench mark would be 0.25 so B
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3 years ago
f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?
Leya [2.2K]

The equivalent expression to \mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}

<h3>What are the equivalent expressions?</h3>

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

  • r(x) = 3x - 1
  • s(x) = 2x + 1

Then the fractional form can be an expression as:

\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}

where;

  • x = 6

\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}

\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}

\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}

Learn more about equivalent expressions here:

brainly.com/question/24734894

#SPJ1

8 0
2 years ago
Use the discriminant to determine the number of real solutions to the quadratic equation. n^2 − n − 6 = 0 What is the number of
Andreas93 [3]

Answer: last option

Step-by-step explanation:

The formula to find the Discriminant is:

D=b^2-4ac

Given the quadratic equation n^2-n-6=0, you can identify that:

a=1\\b=-1\\c=-6

Now, you can substitute values into the formula  D=b^2-4ac, then:

D=b^2-4ac\\D=(1)^2-4(1)(-6)\\D=25

As the Discriminant is greater than 0 (D>0), then the quadratic equation  n^2-n-6=0 has two distinct real solutions.

6 0
4 years ago
Read 2 more answers
A class spends 1 hour 15 minutes on
solmaris [256]

Answer:

1/4

this is fraction of time spent on English language...

5 0
3 years ago
A bicycle store pays $29.62 for a helmet the store sells the helmet for $39.99 find the percent markup
krek1111 [17]
Percent increase = (new number - original number) / original number...* 100
                           = (39.99 - 29.62) / 29.62....* 100
                           = 10.37 / 29.62....* 100
                           = 0.35 * 100
                           = 35% markup <===
8 0
3 years ago
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