Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
f triangle $acb$ to the area of the trapezoid $abcd$? express your answer as a common fraction.
1 answer:
Draw a diagram to illustrate the problem as shown below.
The area of triangle acb is
A₁ = (1/2)*20*h = 10h
The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h
The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8
Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.
You might be interested in
Answer:
30 minutes by bus
Step-by-step explanation:
Equation: b = bus
b = (65 - 5) / 2
b = 60/2
b = 30 mins
Please give Brainliest :)
Answer:
m= y2- y1 / x2 - x1= Slope
change 3/4 to 6/8 and add 6/8 and 1/8 to get 7/8
he walked 7/8 miles in total :)
Let p = number of people that cast their vote.
p = 0.35(15, 000)
p = 5,250
