Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
f triangle $acb$ to the area of the trapezoid $abcd$? express your answer as a common fraction.
1 answer:
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Answer:
Area: 6a^2
Perimeter: 12a^2
Step-by-step explanation:
To find the area of a triangle, use the formula A=1/2 b*h. The base is 3a^2 and the height is 4a^2.
A= 1/2 (3a^2)(4a^2)
A = 1/2 (12a^4)
A = 6a^4
To find the perimeter of the triangle, add each of the sides of the triangle. The third side, the hypotenuse, can be found using Pythagorean theorem.
Now add each of the sides: 3a^2 + 4a^2 +5a^2 = 12a^2