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Bess [88]
3 years ago
13

Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o

f triangle $acb$ to the area of the trapezoid $abcd$? express your answer as a common fraction.

Mathematics
1 answer:
alekssr [168]3 years ago
4 0
Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

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Henry was thinking of a number Henry halves it and gets a an answer of 12.4 what was the original number
jeka94
Answer: 24.8
Explanation: If Henry is halving a number, that means he's dividing it by 2, getting two halves. You would get the original number by undoing that division, or multiplying the product by 2.
2 x 12.4 = 24.8
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3 years ago
Based on the line plot, how many batteries lasted more than 5 1/2 hours? *
babunello [35]

Answer:

5 batteries.

Explanation:

"How many batteries lasted more than 5 1/2 hours?" which means it's counting not only 5 1/2, but 5 3/4 and 6 1/4

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3 years ago
Read 2 more answers
If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)​
marshall27 [118]

Answer:

\large\boxed{(t\times s)(x)=4x^3-28x^2+3x-21}

Step-by-step explanation:

s(x)=x-7\\t(x)=4x^2+3\\\\(t\times s)(x)=t(x)\times s(x)\\\\\text{Substitute:}\\\\(t\times s)(x)=(4x^2+3)(x-7)\\\\\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(t\times s)(x)=(4x^2)(x)+(4x^2)(-7)+(3)(x)+(3)(-7)\\\\=4x^3-28x^2+3x-21

8 0
3 years ago
I will give brainiest to whoever answers correctly !!
alex41 [277]

Answer:

What is the question????

7 0
3 years ago
Which ordered pair is included in the solution set to the following system? y > x2 + 3 y < x2 – 3x + 2 (–2, 8) (0, 2) (0,
I am Lyosha [343]

The ordered pair that is a solution of the system is (-2, 8).

<h3>Which ordered pair is included in the solution set to the following system?</h3>

Here we have the system of inequalities:

y > x² + 3

y < x² - 3x + 2

To check which points are solutions of the system, we can just evaluate both inequalities in the given points and see if they are true.

For example, for the first point (-2, 8) if we evaluate it in the two inequalities we get:

8 > (-2)² + 3 = 7

8 <  (-2)² - 3*(-2) + 2 = 12

As we can see, both inequalities are true. So we conclude that (-2, 8) is the solution.

(if you use any other of the 3 points you will see that at least one of the inequalities becomes false).

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

3 0
2 years ago
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