What is the product of 78 negative 16 negative 7 and negative 114th

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

positive 995,904

Step-by-step explanation:

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What is the slope of the line equation 7x-3y=21

kramer

Equation: 7x - 3y = 21

3y = 7x - 21

Divide both sides by 3,

y = 7/3x - 7

Compare it with principle equation, y = mx + c

Here, slope (m) = 7/3

In short, Your Answer would be: 7/3

Hope this helps!

8 0

3 years ago

"Large Sample Proportion Problem. Surveys were conducted in multiple countries and respondents were asked if they felt political

melomori [17]

Answer: 0.0158

Step-by-step explanation:

Given : The data for the United States is that out of 1,000 sampled, 470 indicated yes, they felt political news was reported fairly.

According to the given information we have,

Sample size : n= 1000

Sample proportion: $\hat{p}=\dfrac{470}{1000}=0.47$

The standard error for proportion is given by :-

$S.E.=\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$S.E.=\sqrt{\dfrac{0.47(1-0.47)}{1000}}$

$S.E.=\sqrt{0.0002491}$

$S.E.=0.0157829021412\approx0.0158$

[Rounded to the nearest four decimal places.]

Hence, the standard error for the confidence interval = 0.0158

6 0

2 years ago

Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than

Fittoniya [83]

Inequation 1:

$\frac{2}{3}x-3 \geq y$

to plot the pairs (x, y) for which the inequation holds, draw the line $y=\frac{2}{3}x-3$

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2:

$y+ \frac{2}{3}x\ \textless \ 4$

$y\ \textless \ - \frac{2}{3} x+ 4
$

draw the lines

i) $y=\frac{2}{3}x-3$ use points (0, -3), (3, -1)

ii) $y=- \frac{2}{3} x+ 4$ use points ( 0, 4), (3, 2)

let's use the point P(3, 3) to see what region of the lines need to be coloured:

$\frac{2}{3}x-3 \geq y$ ;
$\frac{2}{3}(3)-3 \geq 3$
$2-3 \geq 3$ , not true so we color the region not containing this point

$y+ \frac{2}{3}x\ \textless \ 4$
$(3)+ \frac{2}{3}(3)\ \textless \ 4$
$3+ 5\ \textless \ 4$ not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.