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3 years ago

What are these answers please help

Mathematics

1 answer:

Sphinxa [80]3 years ago

4 0

Answer: if it is a positive number then it will always be a positive integer

Step-by-step explanation:

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Pls some answer this for me

galben [10]

Answer:

Use pi then round it like the manual says

Step-by-step explanation:

5 0

2 years ago

P^3•9^2 (P^4•9^n•R^3/R^4)= P^7 9^5 1^7 What is n?

kkurt [141]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

5 0

3 years ago

HELP WILL MARK BRAINLIEST

Trava [24]

Look at the attached picture⤴

Hope this will help u...

7 0

2 years ago

Read 2 more answers

A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability

alex41 [277]

Answer:

the mean is 3

answer choice D

Step-by-step explanation:

60/20

8 0

3 years ago

Read 2 more answers