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cricket20 [7]
3 years ago
5

I NEED HELP ASAP PLEASE NO LINKS!!!

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

1/8

Step-by-step explanation:

I looked it up lol

Lemur [1.5K]3 years ago
5 0

Answer:

1/8

Step-by-step explanation:

2^-3

= 1/2^3 ( The reciprocal of the negative exponent is positive).

= 1/8

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Please show step by step video
Yanka [14]
834/6=139
Each building will get 139 planks
Use long division

6 0
3 years ago
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What is the equation of the line that passes through the point (2,7) and has a slope of 6?
Mumz [18]

Answer:

y= 6x - 5

Step-by-step explanation:

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3 years ago
Can someone please answer this for me
djverab [1.8K]

Answer:

C

Step-by-step explanation

the numbers are decreasing -3

4 0
2 years ago
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Select the correct answer.
Elina [12.6K]

Answer:

  A)  6.86×10⁴

Step-by-step explanation:

You want to write 68600 in scientific notation.

<h3>Expanded form</h3>

The number 68600 can be written in expanded form with exponents as ...

  68600 = 6×10⁴ +8×10³ +6×10² +0×10¹ +0×10⁰

The left-most term of this sum tells you the exponent in scientific notation:

  68600 = 6.86×10⁴

5 0
1 year ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
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