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3 years ago

A sphere has a volume of 2,3041 mm^3 Find the diameter of the sphere.

Mathematics

1 answer:

Elenna [48]3 years ago

3 0

Answer: diameter = 34

Step-by-step explanation:

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A cell phone company charges $40 per month for unlimited calling, and $0.20 per text message sent. If t represents the number of

kotegsom [21]

Answer: 40 + 0.2t

Step-by-step explanation:

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3 years ago

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A car with a tank that holds 11.6 gallons of gasoline is using 1.45 gallons per hour. Is the tank more than half full of gasolin

spayn [35]

No, because 11.6/2 is 5.8 so 5.8 is half of the tank. if it uses 1.45 per hour and it's used for 3.5 hours there will only be 5.075

6 0

3 years ago

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Will the product of a positive number and a negative number be positive or negative? Why?

MA_775_DIABLO [31]

Answer:

negative

Step-by-step explanation:

positive * positive = positive

negative * positive = negative

5 0

3 years ago

5p + 6 = -4p - 8<br> Solve for p

Fofino [41]

9p=-14

p=-14/9 is the answer to the problem

5p+4p+6= -8
9p= -8-6
9p=-14
p= -14/9

7 0

3 years ago

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

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3 years ago

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