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taurus [48]
3 years ago
14

i’m taking a test rn and it’s about domain and range and the equation is x = 2 just correct me if i’m right or wrong and can you

please help me with the answer

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

I think you are correct

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Answer:

Shaded area = 6^2 * ( pi/3 - sqrt(3)/2 )

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Step-by-step explanation:

see solution by same author given in

brainly.com/question/17023327?answeringSource=feedPersonal%2FhomePage%2F2

(question 17023327)

Please refer to the diagram for additional letters and measures.

Let

r=radius (OA and PA) of each circle

Area of sector PAOB

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Area of triangle PAB

= 2* (r cos(60) * r sin(60) /2)

= 2* ((r/2) * r (sqrt(3)/2) /2)

= sqrt(3) * r^2 / 4

= r^2 * sqrt(3)/4

Area of segment AOB

= area of segment PAOB - area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )

By symmetry, area of shaded area

= area of segment AOB  -  area of triangle AOB

= area of segment AOB  -  area of triangle PAB

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= r^2 * ( pi/3 - 2*sqrt(3)/4 )

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Since r = b, we substitute

Shaded area

= b^2 * ( pi/3 - sqrt(3)/2 )

Substitute b=6

area

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= 6.522197 square units

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