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taurus [48]
3 years ago
14

i’m taking a test rn and it’s about domain and range and the equation is x = 2 just correct me if i’m right or wrong and can you

please help me with the answer

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

I think you are correct

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This is   1/2 to 1/10

multiply each fraction by 10:-

= 5 : 1

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A recipe for cookies calls for 1/3 of a cup of sugar per batch. Elena used 5 1/3 cups of sugar to make multiple batch of cookies
shusha [124]

Answer:

she can make 16 batches

Step-by-step explanation: simply multiply 5 by 3 and add 1(for the fraction)

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3 years ago
What is the square root of 64 multiplied by 2
Tamiku [17]

Answer:

its 16

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Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.
Step2247 [10]

After using the property of power, the expressions as a power of the number a is (a^3)^{-2} = a^{-6} , (a^{-1}\cdot a^{-2})^{-3} = a^{9} and ((a^2)^{-2})^2=a^{-8} .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is (a^3)^{-2}.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

Simplifying the expression.

(a^3)^{-2} = a^{3*(-2)}

(a^3)^{-2} = a^{-6}

The second expression is (a^{-1}\cdot a^{-2})^{-3}

Using the property of multiplication of power; (a^m)^n=a^{mn}.

(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}

(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}

Using the property of sum of power a^m\cdot a^n=a^{m+n}

(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}

(a^{-1}\cdot a^{-2})^{-3} = a^{9}

The third expression is ((a^2)^{-2})^2.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=((a^2)^{(-2)\times2})

((a^2)^{-2})^2=(a^2)^{-4}

Again using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=a^{2\times(-4)}

((a^2)^{-2})^2=a^{-8}

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0
1 year ago
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