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boyakko [2]
2 years ago
5

Greg has a piece of rope 18 ft long. He wants to cut it into two pieces so that the longer piece is 2 ft less than 3 times the l

ength of the shorter piece. How long will each piece of rope be? Enter your answers in the boxes. Shorter piece: ft Longer piece: ft.
Mathematics
1 answer:
tankabanditka [31]2 years ago
7 0

The length of the shortest piece is 5, and the longest piece is 13 feet.

Given

Greg has a piece of rope that is 18 ft long.

He wants to cut it into two pieces so that the longer piece is 2 ft less than three times the length of the.

<h3>What is a system of the equation?</h3>

A system of equations is a set of two or more equations that you deal with at one time.

Let the length of the shorter piece be x.

And the length of the longer piece is 3x -2.

Greg has a piece of rope that is 18 ft long.

Then,

\rm \text{longest piece+shortest piece}=18\\\\x+3x-2=18\\\\4x=18+2\\\\4x=20\\\\x=\dfrac{20}{4}\\\\x=5

Therefore,

The length of the shorter piece is x =5.

And the length of the longer piece = 3x -2 = 3(5)-2 = 15-2 = 13

Hence, the length of the shortest piece is 5, and the longest piece is 13 feet.

To know more about the System of equations click the link given below.

brainly.com/question/12895249

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Valentin [98]

Answer:

$133507.33

Step-by-step explanation:

x = number of 6 month periods

y = total money in account

After 10 years:

y = 300x(1.09)^x

y = 300(20)(1.09)^2^0

y = 6000(5.60441077)

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6 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

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