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lana [24]
3 years ago
7

When a pendulum is held high and taut and then is released, the pendulum begins to swing. What’s the correct order of the energy

transformations in this example?
(PE stands for potential energy.)
gravitational PE → elastic PE → thermal energy
gravitational PE → kinetic energy → thermal energy
kinetic energy → elastic PE → thermal energy
kinetic energy → gravitational PE → thermal energy
thermal energy → gravitational PE → kinetic energy
Chemistry
2 answers:
steposvetlana [31]3 years ago
8 0

Answer:

gravitational PE → kinetic energy → thermal energy

Explanation:

In the absence of friction, the mechanical energy which is the sum of potential energy and kinetic energy remains constant. When the pendulum is held high and is motionless, it possesses gravitational potential energy. When it is released, potential energy converts to kinetic energy. At lowest point, the pendulum has kinetic energy only.

In the presence of friction, damping occurs. The motion of pendulum slows down  and the energy dissipates as thermal energy.

Taya2010 [7]3 years ago
4 0

Answer:

gravitational PE → kinetic energy → thermal energy

Explanation:

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a helium balloon has a volume of 2.95 liters at 25 c. the volume of the ballon decreased to 2.25 l after it is placed outside on
OleMash [197]

Answer:

The outside temperature is -45.8°C

Explanation:

When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).

V1 / T1 = V2 / T2

2.95L/298K = 2.25L / T2

(2.95L/298K ) . T2 = 2.25L

T2 = 2.25L . 298K / 2.95L

T2 = 227.2K

T°K - 273 = T°C

227.2K - 273 = -45.8°C

3 0
3 years ago
Please help me with this chem question, I’ll mark you brainiest if it’s right. There’s multiple answers for this one.
Kazeer [188]

Answer:

Option A. KCl (aq)

Option D. Mg(OH)₂(s

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

MgCl₂(aq) + KOH(aq) —>

In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

KOH(aq) —> K⁺(aq) + OH¯(aq)

MgCl₂(aq) + KOH(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)

MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)

Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)

Thus, option A and D gives the correct answer to the question.

8 0
2 years ago
If 56 grams of notrogen are used up by the reaction, how many grams of amonia will be produced? 1N2+3H2--> 2NH3
djverab [1.8K]
1 mole of N2 produces 2 moles of NH3
OR...
14 x 2 grams of N2 produces 2(14 +3) grams of NH3
1 gram of N2 produces 34/28 grams of NH3
therefore, 56 grams produce (34/28 )x 56 =68 grams of NH3 

the answer thus would be 68 grams of NH3
5 0
3 years ago
Which statements true about the total mass of the reactants during a chemical change? (5 points)
Lapatulllka [165]
It is greater than the total mass
5 0
2 years ago
Please someone help mee
Nikitich [7]

Answer:

13.9kj/mol

Explanation:

h = 891 -(393.5 +2*241.8)=1768.1=13.9kj/mol

8 0
3 years ago
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