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Vesna [10]
2 years ago
9

Given the balanced equation representing a reaction:

Chemistry
2 answers:
Radda [10]2 years ago
7 0

Answer: Option (3) is the correct answer.

Explanation:

One of the important factor on which rate of reaction depends is surface area. That is, when a compound is crushed into powdered form then there will be increase in surface area of the compound.

Hence, now more number of particles can interact, therefore, there will be increase in rate of reaction.

Thus, we can conclude that reaction occurs more quickly when powdered iron is used instead of a single piece of iron of the same mass because the powdered iron has a greater surface area than the single piece of iron.

zhenek [66]2 years ago
5 0
The answer is (3). The powdered iron and the piece iron is the same substance and is just different in the shape. So the reason is the power has larger surface area for reaction occurs.
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4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins
aleksley [76]

Answer:

Gold

Explanation:

We are given that

Mass of sample ,m=385 g

Volume ,V=20mL

We have to find the coin is gold or yellow brass.

We know that

Density=\frac{Mass}{volume}

Using the formula

Density=\frac{385}{20}g/mL

Density=19.25g/mL

Density\approx 19.3g/mL

Density of coin=19.3g/mL

Density of gold=19.3g/mL

Hence, the coin is gold.

5 0
3 years ago
Chemical Equations
vagabundo [1.1K]

Answer:

0.712 moles of NO₂ are formed.

Explanation:

First, we need to write the balanced equation:

2 N₂O₅(g) ⇄ 4 NO₂(g) + O₂(g)

From the balanced equation, we can see the relationship between the moles of N₂O₅ and the moles of NO₂. Every 2 moles of N₂O₅ that react, 4 moles of NO₂ are formed. Let us apply this relationship to the information given by the problem (0.356 moles of N₂O₅):

0.356molN_{2}O_{5}.\frac{4molNO_{2}}{2molN_{2}O_{5}} =0.712molNO_{2}

3 0
3 years ago
Convert 16.8 L of nitrogen monoxide gas at STP to grams .
german

Answer:

See explanation

Explanation:

1 mole of a gas occupies 22.4 L

x moles occupies 16.8 L

x = 1 mole *  16.8 L/22.4 L

x = 0.75 moles

number of moles = mass/molar mass

mass =  number of moles  * molar mass

mass =  0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g

the coefficient of the scientific notation answer = 2.25

the exponent of the scientific notation answer = 1

significant figures are there in the answer = 6

the right most significant figure in the answer = 3

2.

number of moles = 12.5g/38g/mol = 0.3289 moles

1 mole occupies 22.4 L

0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole

= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L

the coefficient of the scientific notation answer =7.37

the exponent of the scientific notation answer = 0

significant figures are there in the answer = 6

the right most significant figure in the answer= 3

8 0
3 years ago
Complete the following precipitation reactions with balanced molecular, total ionic, and net ionic equations:
Dmitry [639]

Molecular equation

Hg₂(NO₃)₂ (aq) + KI(aq) ⇒Hg₂I₂(s) + 2KNO₃(aq)

Total Ionic equation

Hg²⁺(aq) + 2NO³⁻(aq) + 2K⁺aq) ⇒Hg₂I₂(s) + 2K⁺(aq) + NO³⁻ (aq)

Net Ionic equation

Hg²⁺(aq) + 2I⁻(aq)  ⇒ Hg₂I₂(s)

<h3>What is the molecular equation?</h3>

Sometimes, a balanced equation is all that is used to refer to a chemical equation. Any ionic substances or acids are represented using their chemical formulas as neutral compounds in a molecular equation. Each substance's state is described in parenthesis after the formula. A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.

The steps listed below can be used to determine the net ionic equation for a specific reaction:

Include the states of each chemical in the balanced molecular equation for the reaction.

To know more about the molecular equation, visit:

brainly.com/question/14286552

#SPJ4

4 0
1 year ago
What does solubility mean
stiv31 [10]

Answer: The ability to be dissolved

Explanation:

4 0
3 years ago
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