When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
given that :
volume = 1.00 L
molarity = 0.500 M
The solution is tripled by dilution but there will be no effect in number of mole by the dilution.
the number of moles = molarity × volume in L
the number of moles = 1 × 0.500
the number of moles = 0.5 mol
Thus, When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
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This is a combustion reaction because it is being combined with oxygen. Then to balance you will put the number of carbons you have or 4 in front of the CO2 and then same with H2. Then you will add up the oxygen and divide it by two to get. 1, (13/2), 4, 5
It would be known as a meth_(insert - ane, - ene, and -yne) hydrocarbon.
1 bond = -ane
2 bonds = - ene
And so on.
The answer should be law of conservation of energy
Answer:
24.45 L
Explanation:
From General gas equation,
PV/T = P'V'/T'.................... Equation 1
Where P = initial pressure, V = Initial volume, T = Initial Temperature, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
make V' the subject of the equation.
V' = PVT'/(TP')................. Equation 2
Given: P = 760 torr, V = 22.4 L, T = 0 °C = (0+273) = 273 K, T' = 25 °C = (25 + 273) = 298 K, P' = 760 torr
Substitute into equation 2
V' = 760(22.4)(298)/(760×273)
V' = 24.45 L.
Hence the volume of the gas = 24.45 L
