Hey there!:
Concentration of NaOH = 0.200 M
Concentration of HNO₃= 0.200 M
Total volume = 50.0 mL + 60.0 mL = 110 mL=> 0.11 L
The neutralization reaction between NaOH and HNO3 :
OH⁻ + H⁺ ----------> H₂O
So :
n ( H⁺ ) = 60 mL * 0.200 M / 1000 mL => 0.012 moles of H⁺
n ( OH⁻ ) = 50 mL 0.200 M / 1000 mL => 0.01 moles of OH⁻
Hence OH⁻ is limiting reagent .
Remaining moles of H⁺ = 0.012 - 0.01 => 0.002 moles
Concentration of H⁺ = 0.002 M / 0.11 L
Concentration of H⁺ = 0.01818 moles/L
Therefore:
pH = - log [ H⁺ ]
pH = - log [ 0.01818 ]
pH = 1.74
Hope that helps!
Answer:
You should follow these steps:
Count each type of atom in reactants and products.
Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.
Repeat steps 1 and 2 until the equation is balanced.
Explanation:
Experimental errors can be of two kinds: human error and analytical error. Analytical error can be corrected easily. You just have to use instruments that are of high precision. For example, instead of using the platform balance, use the analytical balance which displays 4 decimal places to be highly accurate. For the human error, this is subjective. The only way to correct human error is to be more meticulous on your data measurements.
Concrete is classified as a homogeneous mix
