is carried out adiabatically in a constant-volume batch reactor. The rate law is Plot and analyze the conversion, temperature, a
nd concentrations of the reacting species as a function of time. Additional information: Initial Temperature 100C k1 (373 K) 2 103 s1 E1 100 kJ/mol k2 (373 K) 3 105 s1 E2 150 kJ/mol CA0 0.1 mol/dm3 25 J/mol K CB0 0.125 mol/dm3 25 J/mol K (298 K) 40,000 J/mol A 40 J/mol K
1 answer:
Answer:
See explaination
Explanation:
The mole balance for a constant-volume batch reactor is given such as, For a first-order isothermal reaction, the time to reach a given conversion is the same for constant-pressure and constant-volume reactors. Also, the time is the same for a reaction of any order if there is no change in the number of moles.
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<h3>Answer:</h3>
3.5 Newton
<h3>Explanation:</h3>We are given;
Mass of the ball = 140 g
Acceleration = 25 m/s²
Required to find the force;
- According to Newton's second law of motion, the resultant force on a body in motion and the rate of change in linear momentum are directly proportional.
- That is;
- Thus; F = ma , where F is the resultant force, m is the mass and a is the acceleration.
To get the force we substitute the value of m and a in the formula;
Therefore;
F = 0.14 kg × 25 m/s²
= 3.5 N
Hence, the force needed to accelerate the ball is 3.5 N