is carried out adiabatically in a constant-volume batch reactor. The rate law is Plot and analyze the conversion, temperature, a
nd concentrations of the reacting species as a function of time. Additional information: Initial Temperature 100C k1 (373 K) 2 103 s1 E1 100 kJ/mol k2 (373 K) 3 105 s1 E2 150 kJ/mol CA0 0.1 mol/dm3 25 J/mol K CB0 0.125 mol/dm3 25 J/mol K (298 K) 40,000 J/mol A 40 J/mol K
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Answer:
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Explanation:
The mole balance for a constant-volume batch reactor is given such as, For a first-order isothermal reaction, the time to reach a given conversion is the same for constant-pressure and constant-volume reactors. Also, the time is the same for a reaction of any order if there is no change in the number of moles.
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Answer:
Explanation:
The reaction between dimethyl malonate which is an active methylene group with an (∝, β-unsaturated carbonyl compound) i.e methyl vinyl ketone is known as a Micheal Addition reaction. The reaction mechanism starts with the base attack on the β-carbon to remove the acidic ∝-hydrogens and form a carbanion. The carbanion formed(enolate ion) attacks the methyl vinyl ketone(i.e. a nucleophilic attack at the β-carbon) to give a Micheal addition product, this is followed by the protonation to give the neutral product.
Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- AgNO₃: 2 moles
- Zn: 1 mole
- Ag: 2 moles
- Zn(NO₃)₂: 1 mole
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?
<u><em>amount of moles of AgNO₃= 10 moles </em></u>
But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.
<h3>Moles of Ag formed</h3>Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?
<u><em>amount of moles of Ag= 8 moles</em></u>
Then, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.
Learn more about the reaction stoichiometry:
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