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Molodets [167]
2 years ago
14

How many electrons are in the outermost shell of the K+ ion in its ground state?​

Chemistry
1 answer:
ElenaW [278]2 years ago
6 0

Answer:

19 electrons

Explanation:

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1 question content area what is the total number of valence electrons in the lewis structure of sebr2o?
joja [24]

There are 24 valance electrons in the compound.

<h3>What are valence electrons?</h3>

We know that the valence electrons are those that are found on the valence shell of an atom. There are four atoms that can be seen in the compound that is under consideration. The atoms are selenium, bromine (2 atoms) and oxygen.

Given that there are seven valence electrons in bromine and six valence electrons in oxygen and selenium. We have;

2(7 electrons of bromine) + 6 electrons of oxygen + 4 electrons of Se

= 24 electrons

Learn more about valence electrons:brainly.com/question/8906371

#SPJ1

6 0
1 year ago
Which is not a type of mass movement
lana66690 [7]

Answer:

options?

Explanation:

3 0
3 years ago
Read 2 more answers
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
The rays produced in a cathode tube are
wel

Answer:

Electrons

Explanation:

Cathode rays carry electronic currents through the tube. Electrons were first discovered as the constituents of cathode rays. J.J. Thomson used the cathode ray tube to determine that atoms had small negatively charged particles inside of them, which he called “electrons.”

7 0
3 years ago
Read 2 more answers
The two balanced equations (1) and (2) are for reactions in which gaseous carbon dioxide is produced from the combustion of (1)
V125BC [204]

Answer:

2.0 mol of oxygen are consumed.

Step-by-step explanation:

You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.

M_r:   28.0                 44.0

          CO  + ½O₂ ⟶ CO₂ + 67.6 kcal

m/g:   112

<em>Step 1</em>. Convert grams of CO to moles of CO

1 mol CO = 28.0 g CO

Moles of CO = 112 × 1/28.0

<em>Step 2.</em> Convert moles of CO to moles of CO₂.

The molar ratio is 1 mol CO₂ to 1 mol CO

Moles of CO₂ = 4.000 × 1/1

Moles of CO₂ = 4.00 mol CO₂

Option A is <em>wrong</em>.

<em>Step 3.</em> Calculate the amount of heat generated.

q = ΔH

The conversion factor is 67.6 kcal/1 mol CO₂

q = 4.00 × 67.6

q = 270 kJ

Option B is <em>wrong</em>, because it gives the heat generated by 1 mol of CO.

<em>Step 4. </em>Calculate the moles of O₂ consumed

Moles of O₂ = 2.00 mol O₂

Option C is correct.

<em>Step 5.</em> Calculate the moles of CO₂ formed

Already done in Step 2.

Moles of CO₂ = 4.00 mol CO₂

Option D is <em>wrong. </em>

<em> </em>

<em>Step 6</em>. Calculate the moles of O₂ produced

Already done in Step 4.

Moles of O₂ = 2.00 mol O₂

Option E is <em>wrong. </em>

3 0
3 years ago
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