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Aloiza [94]
3 years ago
14

How much time is required to plate out 20.0 g of Zn from a solution containing Zn2+ ions, using a current of 2.00 amperes?

Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer: 494.872mins

Explanation:

M= MrIt÷n

M=20g

Mr=65g/mol

I=2A

1 farad= 96500

For zinc with 2ions

2×96500= 193000

M×n= MrIt

T= M×n÷MrI

t= 20×193000/2×65

t= 3860000/130

t= 29692.307sec

t=29692.307/60

t= 494.872 mins

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Give the formula for an ionic compound formed from each pair of ions
Vera_Pavlovna [14]

Please, find the complete question in the picture attached.

Answer:

1. Na₂O

2. AlF₃

3. MgO

4. Ca₃P₂

Explanation:

1. Na⁺ and O²⁻

An ionic compound will be formed when two ions of opposite charge attract each other.

The positive ion is called cation and the negative ion is called anion.

Thus, every ionic compound has a cation and an anion electrostatically bonded.

The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.

This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.

Simbolically:

Cation:A^{+x}\\ \\ Anion:B^{-y}\\ \\ Compound:A_yB_x

As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.

Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:

  • Na₂O

2. Al³⁺ and F⁻

  • The subscript of Al will be 1 (because the F ion has charge 1-, and the subscript of F will be 3 (because the Al ion has charge +3).

Thus the ionic compound formed by this pair of ions is:

  • AlF₃

3. Mg²⁺ and S²⁻

  • The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:

That results in the formula: Mg₂S₂

Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:

  • MgO

4. Ca²⁺ and P³⁻

  • The charge 2+ from Ca will become subscript 2 for P and the charge 3- whill become subscript 3 for Ca.

Hence, the ionic compound formed by these two ions is:

  • Ca₃P₂

7 0
2 years ago
Hydrogen sulfide is composed of two elements: hydrogen and sulfur. in an experiment, 6.500 g of hydrogen sulfide is fully decomp
LiRa [457]
Hydrogen sulfide = hidrogen + sulfur

       6.500 g                      

a)                             0.384 g   +    x

=> 6.500 = 0.384 + x => x = 6.500 - 0.384 = 6.116 g

Answer: 6.116 g of sulfur must be obtained

b) this experiment demonstrate the conservation of mass.

c) Dalton's atomic model states that the atoms cannot be created, split or be destroyed, and so in a chemical reaction the atoms rearrange but the number of each type of atoms remain constant, so the mass of each type of atoms and the total mass remain constant.
8 0
3 years ago
(100 points+Brainlyest If Correct)
Alisiya [41]

Answer:

a b d

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5 0
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Which type of perspective makes objects look similar to how they look in real life (select the best answer)
olasank [31]
I believe it's fractional perspective
5 0
3 years ago
What is the molarity of a NaOH solution if 32.47 mL is required to titrate 0.6013 g of potassium hydrogen phthalate (C8H5O4K)
Artist 52 [7]

Answer:

0.0907 M

Explanation:

Before you can calculate the molarity, you need to convert grams to moles (via molar mass) and convert mL to L.

(Step 1)

Molar Mass (C₈H₅O₄K):

8(12.011 g/mol) + 5(1.008 g/mol) + 4(15.998 g/mol) + 39.098 g/mol

Molar Mass (C₈H₅O₄K): 204.218 g/mol

0.6013 g C₈H₅O₄K             1 mole
------------------------------  x  ------------------  =  0.00294 moles C₈H₅O₄K
                                          204.218 g

(Step 2)

1,000 mL = 1 L

32.47 mL              1 L
---------------  x  -----------------  =  0.03247 L
                        1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.00294 moles / 0.03247 L

Molarity = 0.0907 M

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