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juin [17]
3 years ago
14

A tree's shadow is 4.8 meters long on level ground, as shown. The angle of elevation from the tip of the shadow to the sun is 50

°. Based on this information, what is the approximate height of the tree? Write a trig equation, show your work and pick your answer. A. 3.1 m B. 3.6 m C. 5.7 m D. 7.5 m
Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

c.

Step-by-step explanation:

tan(50)=x/4.8

then

4.8 times Tan(50)

equals

5.7

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Solve and factorise x^2-8x+16=0
goblinko [34]

Answer:

x=4x therefore the answer is 4x

Step-by-step explanation:

x^2-8x+16=0

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How many significant figures are there In the number 10.76
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Number of Significant Figures: 4

The Significant Figures are 1 0 7 6

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3 3/4 divided by 5 5/8
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Answer:

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Step-by-step explanation:

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Read 2 more answers
Square root of 50 + square root of 18
skelet666 [1.2K]

if ya asking for simpliicatio

remember that \sqrt{ab}=(\sqrt{a})(\sqrt{b})

and

\sqrt{a^2}=(\sqrt{a})(\sqrt{a})=a

\sqrt{50}+\sqrt{18}=

factor

(\sqrt{2})(\sqrt{5})(\sqrt{5})+(\sqrt{2})(\sqrt{3})(\sqrt{3})=

(\sqrt{2})(5)+(\sqrt{2})(3)=

5\sqrt{2}+3\sqrt{2}=

8\sqrt{2}

5 0
3 years ago
What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir
I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0
3 years ago
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