= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
Answer:
x = 20
Step-by-step explanation:
The three angles form a straight line so they add to 180 degrees
x+ 100 +3x = 180
Combine like terms
100+4x= 180
Subtract 100 from each side
100+4x-100= 180-100
4x= 80
Divide each side by 4
4x/4 = 80/4
x = 20
3k²+11k+6, or (k+3)(3k+2), which is the 3rd one. :)
Answer:
Grapes 12 lbs
Apples 20 lbs
Oranges 6 lbs
Cantaloupe 15 lbs
Peaches 15 lbs.
Step-by-step explanation:
Sammy has bought 12 lbs of Grapes.
Now, weight ration of Apples to Grapes is 5 : 3
Therefore, he bought Apples of 
lbs
The wight ration of Grapes to Oranges is 4 : 2
Therefore, he bought Oranges of 
lbs
Again, the weight ratio of Cantaloupe to Apples is 3 : 4
Therefore, he bought Cantaloupe of 
lbs
Finally the weight ratio of Oranges to Peaches is 2 : 5
Therefore, he bought Peaches of 
lbs
(Answer)
Answer:
12
Step-by-step explanation:
(64)^½ + (64)^⅓
(8²)^½ + (4³)^⅓
8 + 4
12
