Answer:
The answer is below
Step-by-step explanation:
The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.
Therefore:
∠MON = ∠MOP + ∠NOP (angle addition postulate)
Substituting values gives:
124 = (2x + 1) + (2x + 1)
124 = 2x + 2x + 1 + 1
124 = 4x + 2
subtracting 2 from both sides of the equation:
124 - 2 = 4x + 2 - 2
4x = 122
Dividing through by 4:
4x / 4 = 122 / 4
x = 30.5
Therefore ∠MOP = 2x + 1 = 2(30.5) + 1 = 62°, ∠NOP = 2x + 1 = 2(30.5) + 1 = 62°
∠MOP = 62°, ∠NOP = 62°
Y = x² - 4x + 4
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
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<span>
Answer: 4.47 units</span>
Answer:
C. 139°
Step-by-step explanation:
Given:
m<A = 62°
m<B = 77°
Required:
Find m<1
Solution:
Since ∆ABC is similar to ∆DEF, therefore:
<A ≅ <D, which means m<D = 62°
<B ≅ <E, which means m<E = 77°
<C ≅ <F
Therefore, based on exterior angle theorem:
m<1 = m<D + m<E
m<1 = 62° + 77° (substitution)
m<1 = 139°
Its A,have a nice day! :))))))
Answer:
Answer: Option A F(x)=
Explanation:
Quadratic function is the function which has degree two
Degree is the highest power of a polynomial
In option B we have |x| in which degree is one hence, discarded
In option C we have in which degree is three hence, discarded
In option D we have x which is a linear function being of degree one. Hence, discarded.
