Plss help answer true or false

The senior class want to play a practical joke on the principal, who was a former college basketball star. They want to fill his

steposvetlana [31]

The number of basketball that will fill up the entire office is approximately 16,615.

Recall:

Volume of a spherical shape = $\frac{4}{3} \pi r^3$

Volume of a rectangular prism = $l \times w \times h$

Given:

Diameter of basketball = 9.5 in.

Radius of the ball = 1/2 of 9.5 = 4.75 in.

Radius of the ball in ft = 0.4 ft (12 inches = 1 ft)

Dimension of the office (rectangular prism) = 20 ft by 18 ft by 12 ft

First, find the volume of the basketball:

Volume of ball = $\frac{4}{3} \pi r^3 = \frac{4}{3} \times \pi \times 4.75^3\\$

Volume of basketball = $448.92 $ in^3$

Convert to $ft^3$

$1728 $ in.^3 = 1 $ ft^3$

Therefore,

Volume of basketball = $\frac{448.92}{1728} = 0.26 $ ft^3$

Find the volume of the office (rectangular prism):

Volume of the office = $20 \times 18 \times 12 = 4,320 $ ft^3$

Number of basket ball that will fill the office = Volume of office / volume of basketball

Thus:

Number of basket ball that will fill the office = $\frac{4,320}{0.26} = 16,615$

Therefore, it will take approximately 16,615 balls to fill up the entire office.

Learn more here:

brainly.com/question/16098833

6 0

2 years ago

Find mMK................

Gnesinka [82]

Answer:

Approximately mMK is 53 degrees

Step-by-step explanation:

Here, we want to find the length of MK

As we can see, we have a right triangle at LNK

so

let us find the angle at L first

9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L

so the trigonometric identity that connects adjacent to the hypotenuse is the cosine

It is the ratio of the adjacent to the hypotenuse

So;

cos L = 9/15

L = arc cos (9/15)

L = 53.13 degree

Approximately, L = 53 degrees

so now, we want to get the arc length MK

We are to use the angle-arc relationship here

Using this; arc length MK is equal to the measure of L at the center which is 53 degrees

3 0

2 years ago

Tony has a hosepipe. The length of the hosepipe is 20 m. Tony stores the hosepipe on a reel. The weight of the reel is 1.4 kg. 1

harina [27]

Answer:

the total weight of the hosepipe and the reel is 7.4 kg

Step-by-step explanation:

First, we need to find the weight of the hosepipe, we know that 1/2 metre of the hosepipe has a weight of 150 grams, therefore we can conclude that 1 meter has a weight of (150)(2) = 300 grams.

If one meter weighs 300 grams, then 20 meters have a weight of $20(300) = 6000$ grams. But since 1000 grams are 1 kg, this would be equivalent to 6 kg.

Now, to find the total weight of the hosepipe and the reel we are going to sum up the 2 weights:

Total weight = hose pipe weight + reel weight

Total weight = 6 kg + 1.4 kg

Total weight = 7.4 kg.

Therefore, the total weight of the hosepipe and the reel is 7.4 kg

8 0

2 years ago

What is the veritable expression of A number plus the product of the number minus 5 and 7

vivado [14]

Answer:

x + 7(-5)

Step-by-step explanation:

Not sure if this is right or not...

5 0

3 years ago

Which of the following inequalities is graphed above?

kobusy [5.1K]

Answer:

1st option

y=-3/8x+3

6 0

2 years ago