All categories

3 years ago

PLEASE HELLPPPP TYYY Explain how calculating the surface area of a prism differs from a pyramid.

Mathematics

1 answer:

raketka [301]3 years ago

6 0

Answer:

To find the surface area of a prism, find the area of a base and double it since the areas of the two bases are always equal. Then find the area of each side face, and add to the area of the bases. A pyramid has one base and triangular sides.

Step-by-step explanation:

You might be interested in

A stadium has 47,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in

mote1985 [20]

A:23,500 seats
B and C: both have 11,750 seats

7 0

3 years ago

Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2

cupoosta [38]

Answer:

b is the answer

Step-by-step explanation:

7 0

3 years ago

What is

Sergeeva-Olga [200]

Answer:

Standard form of the equation is:

∴ $3x+y=23$

Step-by-step explanation:

Given equation:

$y-2=-3(x-7)$

To convert the given equation to standard form of equation:

$A(x)+B(y)=c$

Using distribution.

$y-2=(-3x)+(-3\times-7)$

$y-2=-3x+21$

Adding 2 both sides.

$y-2+2=-3x+21+2$

$y=-3x+23$

Adding $3x$ to both sides.

$3x+y=3x-3x+23$

∴ $3x+y=23$

6 0

3 years ago

Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$

Viktor [21]

When $n=0$ , we have

$5^{3^0} + 1 = 5^1 + 1 = 6$

$3^{0 + 1} = 3^1 = 3$

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for $n=k$ , that

$3^{k + 1} \mid 5^{3^k} + 1$

Now for $n=k+1$ , we have

$5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)$

so we know the left side is at least divisible by $3^{k+1}$ by our assumption.

It remains to show that

$3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1$

which is easily done with Fermat's little theorem. It says

$a^p \equiv a \pmod p$

where $p$ is prime and $a$ is any integer. Then for any positive integer $x$ ,

$5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3$

Furthermore,

$5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3$

which goes all the way down to

$5^{3^k} \equiv 5 \pmod 3$

So, we find that

$\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3$

QED

5 0

1 year ago

Solving Systems by Addition method

balandron [24]

-4x+0y=-8
=> x=2
substitute 2 into either function for y
it will come out the same and u will have solution
Note, if slopes or coefficient of x are the same => no solution because lines are parallel
Follow! and give me a brainliest plz

5 0

3 years ago