Your answer is the third one. WHen it comes to system of equations, this will cancel out 4a, therefore isolating the variable. That turns the equation into -2b=-5.
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
Hypotenuse legs
6 units arrowBoth 5 units, 1 unit
5 units arrowBoth 2 units, 3 units
8 units arrowBoth 5 units, 2 units
3 units arrowBoth 1 unit, 2 unit
Step-by-step explanation:
i got this because if u add
5+1= 6 units
2+3=5 units
5+2=8 units
1+2=3 units
Answer:
88
Step-by-step explanation:
(17 * 11 = 187) + (9 * -11 = -99)
187 - 99 = 88
