Yes it is linear since it's in the standard form Ax+By = C
A = 2
B = -8
C = 16
Answer:
A
Step-by-step explanation:
how long is the ball in the air ?
that is the same as asking : after how many seconds will the ball hit the ground (= reach the height of 0) ?
so, that means we need to find the zero solution of h(t).
at what t is h(t) = 0 ?
when at least one of the factors is 0 :
2(-2 - 4t)(2t - 5)
we have 3 factors
2 : can never be 0.
(-2 -4t) : can only be 0 for negative t, which does not make sense in our scenario (we cannot go back in time, only forward).
(2t - 5) : is 0 when 2t = 5 or t = 2.5
so, A is the right answer.
FYI : the starting height (on the hill) is given by t = 0 :
2(-2 - 0)(0 - 5) = 2×-2×-5 = 20 ft
F + 0.3 < 1.7
Subtract 0.3 on both sides
F < 1.4
Your final answer is F < 1.4
Answer:
2sinθ + cosθ = 2
Step-by-step explanation:
12 cos θ - 16 sinθ = 0
=> 3 cos θ -4 sin θ = 0
=> tanθ = 3/4
let P = 3x
B = 4x
=> H= 5x
=> sinθ = P/H = 3/5
cosθ = B/H = 4/5
2sinθ + cosθ
= 2× 3/5 + 4/5
= 6/5+4/5
= 10/5
= 2
=> 2sinθ + cosθ = 2
