Answer:
y = -1/2x + 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
Need:
First, let's look at the identities:
sum: 
difference: 
The question asks to find sin(A - B); therefore, we need to use the difference identity.
Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.
sin(A) = 
cos(A) = 
sin(B) = 
cos(B) = 
Plug these values into the difference identity formula.
Multiply.
Add.
This is your answer.
Hope this helps!
Answer:
Find what <u>both fractions</u> are <u>divisible</u> by.
Step-by-step explanation:
Take 
and if needed, use a multiplication tabel to help you figure out what both numbers are divisible by. 5 and 15 are both divisible by 5. Now you can reduce the answer to 
.
Hope this helps!
-Coconut;)
Answer:
The sample space is:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
Explanation:
The <em>sample space </em>is the set of all the possible outputs, i.e. the possible different combinations that can be choosen.
Use the letters T, B, and X to represent, respectively, table height, bar height, and XL height,
Use letters N, W, and K to represent, respectively, the colors brown, white and black.
Each combination consists of a height (T, B or X) and a color (N, W, K); thus, your sample space shall have 3 × 3 different combinations. These are:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
Answer:
Step-by-step explanation:
Thank your for revising and improving the image.
Assuming DF is a straight line,
Given E is the mid-point of DF
mCE = mGF
CE || GF
Then
mDE = mEF (E midpoint of DF)
Angle DEC = Angle EFG (corresponding angle, DF transversal of parallel lines CE and GF)
mCE = mGF (given)
Then triangles DCE and EGF are congruent by reason SAS (side-angle-side)
