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levacccp [35]
3 years ago
11

Find the difference (2ab+7a+1)-(8ab+9)

Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Hello.

The answer is: −6ab+7a−8

Distribute the Negative Sign:

=2ab+7a+1+−1(8ab+9)

=2ab+7a+1+−1(8ab)+(−1)(9)

=2ab+7a+1+−8ab+−9

Combine Like Terms:

=2ab+7a+1+−8ab+−9

=(2ab+−8ab)+(7a)+(1+−9)

=−6ab+7a+−8

Have  a nice day

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Answer:

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Step-by-step explanation:

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Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

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Product 1     ( x₁ )       30             0.5              1

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Product 3    ( x₃ )       20             0.75             0.5

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Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

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General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

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0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

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x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

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