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egoroff_w [7]
2 years ago
9

Is the graphed function linear?

Mathematics
2 answers:
djyliett [7]2 years ago
5 0
Nooooooooooooooooooooooo
Sliva [168]2 years ago
5 0
Nope no it’s not :] it is not
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4x(3x – 7) – 19x2<br> Simplify the expression above?
Varvara68 [4.7K]

this is the simplified answer:

-7x *(x+4)

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A box holds 42 pieces of red construction paper and 18 pieces of blue construction paper. A piece of paper is pulled out of the
choli [55]
77
the answer is 77
for every 42 there is 18
42:18 simplify 
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Plz solve anyone I having trouble answering this someone respond fast
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Step-by-step explanation:

3 0
3 years ago
A math class is having a discussion on how to determine if the expressions 4x-x+5 and 8-3x-3 are equivalent using substitution.
docker41 [41]

Okay. In my opinion, all the class has to do is simplify the expressions and compare. But they want to substitute instead.

Well then.

First, let's notice that these are linear expressions, meaning that if they are equivalent then all their values match up.

Number 1 is not a good one. Just because they're both positive doesn't mean anything; they have to be <em>the same.</em>

This also eliminates 3.

Number 2 is a good one, but it's not as reliable. If, for instance, the two expressions are <em>not </em>equivalent and you get lucky enough to pick that one value they intersect at (or have in common), then you'd be wrong when you say they are equivalent.

Number 4 makes the most sense because if both expressions are equivalent, then every value matches up. If not, then only one will. So having two values to substitute will most definitely answer the class question.

Hope this helps, let me know if I messed up! ;)

5 0
3 years ago
Read 2 more answers
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
2 years ago
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