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3 years ago

Consider z = 3StartRoot 3 EndRoot + 3i. What happens to the modulus and argument when z is raised to the 4th power?

Mathematics

1 answer:

exis [7]3 years ago

6 0

Answer:

It's A

Step-by-step explanation:

Just took it and it matches

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In circle A shown below, m is 67° and m is 74°. What is m∡FDE?

deff fn [24]

Use this theorem: in a circle, the measure of an angle formed by two chords that intersect inside the circle is half the sum of the arcs formed by the chords.

In this case the sum of the arcs formed by the chords is 67° + 74° = 141 °, then the half is 141° / 2 = 70.5°.

Answer: 70.5°

8 0

3 years ago

To solve for y in the equation 2y + y = 5, what first step would need to be taken? Subtract 2 from each side. Add 2y and y. Subt

cricket20 [7]

Answer:

Add 2y and y.

Step-by-step explanation:

you have to combine what is common

plz give brainliest

4 0

3 years ago

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers

What is the measure of ∠H? 1. 115 2. 65 3. 50 4. 25

ddd [48]

Answer:

Step-by-step explanation:

Since FG is congruent to FH, angles FGH and FHG are congruent since angles opposite congruent sides in a triangle are congruent.

3 0

2 years ago

A movie rental kiosk charges a $25 membership fee and $3 per movie. An online movie service charges a $20 membership fee and $4

mylen [45]

25+3m=20+4m
25=20+m
5=m

7 0

3 years ago