It depends.... lets say that a mom is a carrier of colorblindness, so only one of her sons will have colorblindness and one of her daughters will be a carrier but if it is on both X's (of the female's) then both of her daughters will be carriers and her sons will both be colorblind.
The answer to your question is C!
Answer:
The correct answer would be:
- Genotype ratio: 1 (PP) : 2 (Pp) : 1 (pp)
- Phenotypic ratio: 3 (polka-dot tails) : solid colored tail
The genotype of both parents is Pp (heterozygous).
Thus, both the parent would produce two types of gametes which are P and p.
The cross would result in the production of offspring with three types of genotype PP, Pp, and pp in 1:2:1.
Offspring with PP and Pp will have a polka-dotted tail as it is the dominant trait.
Thus, the phenotype ratio would be 3 (polka-dotted tail) : 1 (solid colored tail).