Answer:
Electric potential = 0.00054 V
Explanation:
We are given;
Charge; q = 3 pC = 3 × 10^(-12) C
Radius; r = 2 cm = 0.02 m
Formula for the electric potential of this surface will be;
V = kqr
Where;
K is a constant = 9 × 10^(9) N⋅m²/C².
Thus;
V = 9 × 10^(9) × 3 × 10^(-12) × 0.02
V = 0.00054 V
Answer:
2,500 watts
Explanation:
I got this answer right on a test. I hope it works for you to.
50 *15=750
work is force time distance times angle between both vectors
here the angle is 0.
Answer:
1.52905 seconds
4.58715 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
= Coefficient of friction = 0.4
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration = 
Equation of motion

It will take 1.52905 seconds for the block to slow down

The block will travel 4.58715 m before it stops