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MAXImum [283]
3 years ago
5

What is the degree of precision of the graduated cylinder 0.01 mL 0.1 mL 1 mL 10 mL

Physics
2 answers:
Elodia [21]3 years ago
5 0

Answer:

0.01 ml

Explanation:

Graduated cylinder is used to measurement of volume of liquid.Generally it gives precise result up to 2 digit or up to 3 digit.

Graduated cylinder are of different types .10 mL graduated cylinder measure up to 2 digit while 100 mL graduated cylinder measure up to 1 digit .

So here it is not size of cylinder is not specified so for most precise result the degree of precision of graduated cylinder will be 0.01 mL (up to 2 didgit).

enot [183]3 years ago
4 0
I believe it is 0.1mL or letter B on Edgenuity.
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Zanzabum

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3 years ago
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Please left home at 8 AM to spend the day at in amusement park. He arrived at the park, which was 150 KM from his house, at 10 A
antiseptic1488 [7]

Answer:

v=\frac{150km}{2h}=75\frac{km}{h}

Explanation:

We can use the equation for the speed

v=\frac{x}{t}

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v=\frac{150km}{2h}=75\frac{km}{h}

I hope this useful for you

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3 0
3 years ago
Which is the correct order from least amount of atomic (particle) movement to the most amount of atomic particle movement?
babymother [125]

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In liquids, the particles are close together and they move with random motion in the container. The particles move rapidly in all directions but there is more colision between itself even more than particles in gases. This means that the particles here are MORE FASTER THAN THAT OF THE SOLID.

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8 0
3 years ago
An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields a
My name is Ann [436]

Answer:

The velocity is  v =  5838 \ m/s

Explanation:

From the question we are told that

   The electric field is E  =  2.09 kV/m =  2.09 *10^{3} \ V/m

    The magnetic field is  B  =  0.358 \ T

     

Generally the force experienced by the electron due to the magnetic field is

         F_m  =  qvB

Generally the force experienced by the electron due to the electric  field is

       F_e =  qE

Since from the question the net force is zero  then

     F_e =  F_m

=>    v =  \frac{E}{B}

Substituting values

      v =  \frac{2.09*10^{3}}{0.358 }

    v =  5838 \ m/s

     

8 0
3 years ago
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